Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreFactorise 3x5 – 6x4 – 2x3 4x2 x – 2 asked May 21, 19 in Class VIII Maths by priya12 (12,625 points) factorizationFactorise 5 x 2 y − 1 5 x
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Factorise x^4-y^4+x^2-y^2-Factorise 49(X Y)2 9(2x Y)2 CISCE ICSE Class 8 Textbook Solutions 6351 Important Solutions 5 Question Bank Solutions 7027 Concept Notes & Videos 1 Syllabus Advertisement Remove all ads Factorise 49(X Y)2 9(2x Y)2 Mathematics Sum Factorise 49(xFactorise 25(2x Y)2 16(X Y)2 CISCE ICSE Class 8 Textbook Solutions 6351 Important Solutions 6 Question Bank Solutions 7107 Concept Notes & Videos 196 Syllabus Advertisement Remove all ads Factorise 25(2x Y)2 16(X Y)2 Mathematics Sum Factorise


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If the polynomial k 2 x 3 − kx 2 3kx k is exactly divisible by (x3) then the positive value of k is ____;SolutionShow Solution 75 (x y) 2 48 (x y) 2 = 3 25 (x y) 2 16 (x y) 2 = 3 {5 (x y) 2 } {4 (x y)} 2 Using a 2 – b 2 = (a b) (a – b) = 3 5 (x y) 4 (x y) 5 (x y) 4 (x y) = 3 5x 5y 4x 4y 5x 5y 4x 4y = 3 (9x y) (x 9y) · Ex 141, 3 Factorise (i) 𝑥^2 𝑥𝑦 8𝑥 8𝑦𝑥^2 𝑥𝑦 8𝑥 8𝑦 = (𝑥^2 𝑥𝑦) (8𝑥 8𝑦)Both have x as common factorBoth have 8 as common factor = 𝑥 (𝑥𝑦)8 (𝑥𝑦)Taking (𝑥𝑦) common = (𝒙𝒚) (𝒙 8)
· It can be factored as x^2 y^2 = (xy)(xy) Notice that when you multiply (xy) by (xy) then the terms in xy cancel out, leaving x^2y^2 (xy)(xy) = x^2xyyxy^2 = x^2xyxyy^2 = x^2y^2 In general, if you spot something in the form a^2b^2 then it can be factored as (ab)(ab) For example 9x^216y^2 = (3x)^2(4y)^2 = (3x4y)(3x4y)This is true of the "difference of squares" you sent us, x 2 y 2 Once you think you know the factors you can check by multiplication Here are three possibilities for factorizations of x 2 y 2 (x y)(x y) (x y)(x y) (x y)(x y) Expand each of them and see which simplifies to x 2 y 2Factor Consider x^ {2}y^ {2}xy22xy as a polynomial over variable x Consider x 2 y 2 x y − 2 2 x y as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest power x^ {2} and m divides the constant factor y^ {2}y2 One such factor is xy1
Factorise (xy) 2 7(x 2y 2)12(xy) 2 Share with your friends Share 2 Well done Thunder Sam Keep it up!!6 ; · So, in your case, a = x y, b = 8 And the factorisation is (x y 8)(x y 8) 1 1 frak1a Lv 6 1 decade ago It is the difference of 2 squares 0 1 Still have questions?Factorise 75(x y)2 48(x y)2 The sum of first n natural numbers is given by the expression n^2 /2 n/2


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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Factorise `x^2xyxzyz`Factorise 1 3x 3y 4(x y)2 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries1711 · Therefore, by using the identity (xy) 2 = x 22xyy 2 p 2 –10p25 = (p5) 2 (iii) 25m 2 30m9 Ans Given 25m 2 30m9 Since, 25m 2 , 30m and 9 can be substituted by (5m) 2, 2×5m×3 and 3 2 respectively we get, = (5m) 2 2×5m×3 3 2 Therefore, by using the identity (xy) 2 = x 2 2xyy 2 25m 2 30m9 = (5m3) 2 (iv) 49y 2 84yz36z 2 Ans Given 49y 2 84yz36z 2


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Divide y, the coefficient of the x term, by 2 to get \frac{y}{2} Then add the square of \frac{y}{2} to both sides of the equation This step makes the left hand side of the equation a perfect square∵ x4 (y z)4 = x22 (y z)22 = (x2) (y z)2 (x2) (y z)2 Using a2 b2 = (ab)(ab)We can factorise x2 (y z)2 further as x2 (y z)2Since x^2y^2=\frac12\left((xy)^2(xy)^2\right) the minimum comes when xy is smallest, that is 1 if xy is odd Thus, the minimum is \frac12\left((xy)^21\right) Since x 2 y 2 = 2 1 ( ( x y ) 2 ( x − y ) 2 ) the minimum comes when ∣ x − y ∣ is smallest, that is 1 if x y is odd


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· x^2xy y^2 this equation can't be factor because there is no two numbers whose product and sum is oneFactorise the following (i) 4x^2 9y^2 25z^2 12xy 30yz xz (ii) 25x^2 4y^2 9z^2 – xy 12yz – 30xz asked Oct 30, in Algebra by Darshee ( 491k points) algebra · Ex 141, 2 (Method 1) Factorise the following expressions (x) a𝑥^2y bx𝑦^2 cxyza𝑥^2y = a × 𝑥^2 × y = a × 𝑥 × 𝑥 × yb𝑥𝑦^2 = b × 𝑥 × 𝑦^2 = b × 𝑥 × y × yc𝑥𝑦𝑧 = c × 𝑥 × y × zSo, x and y are the common factorsa𝑥^2y b〖𝑥𝑦〗^2 c𝑥𝑦𝑧 = (a × 𝑥 × 𝑥 × y) (b × 𝑥 × y × y) (c × 𝑥 × y


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0118 · Explanation Making m = x −y n = y −z p = x −z we have m2 n2 p2 = 2(x2 y2 z2 − x ⋅ y − x ⋅ z −y ⋅ z) then x2 y2 z2 −x ⋅ y − x ⋅ z − y ⋅ z = 1 2((x − y)2 (y − z)2 (x −z)2)Get your answers by asking now Ask Question 100 Join Yahoo Answers and get 100 points today Join · Read as factorize x y whole squared 2(xy) Yahoo Answers is shutting down on May 4th, 21 (Eastern Time) and beginning April th, 21 (Eastern Time) the Yahoo Answers website will be in readonly mode


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Factorise a2b – b3 Using this result find the value of 1012 x 100 – 1003 asked May 23, 19 in Class VIII Maths by muskan15 ( 3,440 points) factorizationClick here👆to get an answer to your question ️ Factorise xy(z^2 1) z(x^2 y^2)Please see the explanation x(x y)^2 xy(x y) =x(xy)(xy y) =x^2(xy) (x y)^2 10(x y)25 Using a^22abb^2=(ab)^2 =(xy) 5^2=> Or =(xy5)^2 x^2


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Share It On Facebook Twitter Email 1 Answer 1 vote answered May 15, by Subnam01 (5k points) selected May 16, by Puskar Best answer 15x 3 y 2 z = 3 × 5 × x × x × x × y × y × zYou factor as follows Put a = (xy) Then 3(xy)^2 2(xy) becomes 3a^2 2a which is very easy to factor since a divides into each term Clearly 3a^2–2a =Case 2 xy1=(xy1) Lets take Case 1 xy1=xy1 => 2=0 This means that if we assume that there exists a value of (xy) which satisfies the Case 1 equation, then 2 and 0 would be equal Since that is absurd, our initial assumption was wrong So, there's no common answer to your equation and the Case 1 equation For Case 2 xy1=(xy1) => 2x2y=0 => xy=0


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Factorise fully 4(x y)^2 9(x y)^2 2 See answers aleighablock878 aleighablock878 Answer ( 5x y ) ( x 5y ) or 5x^2 5y^2 26xy irspow irspow Answer Stepbystep explanation 4(x^22xyy^2)9(x^22xyy^2) 4x^28xy4y^29x^218xy9y^25x^226xy5y^25x^2xy25xy5y^2x(5xy)5y(5xy) (x5y)(5xy) or you can also remove theClick here👆to get an answer to your question ️ Factorise x^2(y z) y^2 (z x) z^2(x y)To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Factorise `x^4x^2y^2y^4`


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What must be subtracted from 4x^42x^36x^22x6 so that the result is exactly divisible by 2x^2x1?Here is your solution☺ =============================== To factorise x² y²/100 => x² ( y/10)² => ( x y/10 ) ( x y/ 10) ♦ Note a² b² = (a b) (a b) here this identity is used =============================== Thanks☺Factorise {eq}\displaystyle (x y)^2 9 (x y) {/eq} Factorization when multiplied the product of the polynomial expression together they give the polynomial expression again is the


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View Full Answer (xy) 27(x 2y 2)12(xy) 2 now by using a 2b 2 =(ab)(ab), we have (xy) 27(xy)(xy)12(xy) 2 we take xy = z and xy =a now we have, z 27za12a 2 = z 23za4za12a 2 = z(z3)4a · x^2 2xy y^2 = (x y)(x y) = (x y)^2"y is a root" simply means that the only way we can get the thing to add up to zero, is to make x = y for example, if x = 3 and y = 3, then we get x^2 2xy y^2 = 9 2(3)(3) 9 = 9 18 9 = 0 or (x y)^2 = (33)^2 = 0^2 = 0However, our factorization will work for any value of x and yYou can observe that $xy = (xy)$ So both $x^2y^2$ and $xy$ have $xy$ as a factor You can use these info to get below factorization $$ x^2 y^2 x y = (xy)(xy)(xy) = (xy1)(xy


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Factorise `x^32x^2x2` Factorise `x^32x^2x2` Watch later Share Copy link Info Shopping Tap to unmute If playback doesn't begin shortly, try restarting your deviceClick here👆to get an answer to your question ️ Factorise 2(x y)^2 9(x y) 52x27xy5y2 Final result (5y 2x) • (x y) Step by step solution Step 1 Equation at the end of step 1 ((0 (2 • (x2))) 7xy) 5y2 Step 2 Equation at the end of step 2 ((0 What is the degree of \displaystyle{9}{x}{y}^{{3}}{z}^{{6}} ?


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