[最も好ましい] factorise (x y)^2-(x-y)^2 461700-Factorise x^4-y^4+x^2-y^2

Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreFactorise 3x5 – 6x4 – 2x3 4x2 x – 2 asked May 21, 19 in Class VIII Maths by priya12 (12,625 points) factorizationFactorise 5 x 2 y − 1 5 x

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Factorise x^4-y^4+x^2-y^2

Factorise x^4-y^4+x^2-y^2-Factorise 49(X Y)2 9(2x Y)2 CISCE ICSE Class 8 Textbook Solutions 6351 Important Solutions 5 Question Bank Solutions 7027 Concept Notes & Videos 1 Syllabus Advertisement Remove all ads Factorise 49(X Y)2 9(2x Y)2 Mathematics Sum Factorise 49(xFactorise 25(2x Y)2 16(X Y)2 CISCE ICSE Class 8 Textbook Solutions 6351 Important Solutions 6 Question Bank Solutions 7107 Concept Notes & Videos 196 Syllabus Advertisement Remove all ads Factorise 25(2x Y)2 16(X Y)2 Mathematics Sum Factorise

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If the polynomial k 2 x 3 − kx 2 3kx k is exactly divisible by (x3) then the positive value of k is ____;SolutionShow Solution 75 (x y) 2 48 (x y) 2 = 3 25 (x y) 2 16 (x y) 2 = 3 {5 (x y) 2 } {4 (x y)} 2 Using a 2 – b 2 = (a b) (a – b) = 3 5 (x y) 4 (x y) 5 (x y) 4 (x y) = 3 5x 5y 4x 4y 5x 5y 4x 4y = 3 (9x y) (x 9y) · Ex 141, 3 Factorise (i) 𝑥^2 𝑥𝑦 8𝑥 8𝑦𝑥^2 𝑥𝑦 8𝑥 8𝑦 = (𝑥^2 𝑥𝑦) (8𝑥 8𝑦)Both have x as common factorBoth have 8 as common factor = 𝑥 (𝑥𝑦)8 (𝑥𝑦)Taking (𝑥𝑦) common = (𝒙𝒚) (𝒙 8)

 · It can be factored as x^2 y^2 = (xy)(xy) Notice that when you multiply (xy) by (xy) then the terms in xy cancel out, leaving x^2y^2 (xy)(xy) = x^2xyyxy^2 = x^2xyxyy^2 = x^2y^2 In general, if you spot something in the form a^2b^2 then it can be factored as (ab)(ab) For example 9x^216y^2 = (3x)^2(4y)^2 = (3x4y)(3x4y)This is true of the "difference of squares" you sent us, x 2 y 2 Once you think you know the factors you can check by multiplication Here are three possibilities for factorizations of x 2 y 2 (x y)(x y) (x y)(x y) (x y)(x y) Expand each of them and see which simplifies to x 2 y 2Factor Consider x^ {2}y^ {2}xy22xy as a polynomial over variable x Consider x 2 y 2 x y − 2 2 x y as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest power x^ {2} and m divides the constant factor y^ {2}y2 One such factor is xy1

Factorise (xy) 2 7(x 2y 2)12(xy) 2 Share with your friends Share 2 Well done Thunder Sam Keep it up!!6 ; · So, in your case, a = x y, b = 8 And the factorisation is (x y 8)(x y 8) 1 1 frak1a Lv 6 1 decade ago It is the difference of 2 squares 0 1 Still have questions?Factorise 75(x y)2 48(x y)2 The sum of first n natural numbers is given by the expression n^2 /2 n/2

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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Factorise `x^2xyxzyz`Factorise 1 3x 3y 4(x y)2 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries1711 · Therefore, by using the identity (xy) 2 = x 22xyy 2 p 2 –10p25 = (p5) 2 (iii) 25m 2 30m9 Ans Given 25m 2 30m9 Since, 25m 2 , 30m and 9 can be substituted by (5m) 2, 2×5m×3 and 3 2 respectively we get, = (5m) 2 2×5m×3 3 2 Therefore, by using the identity (xy) 2 = x 2 2xyy 2 25m 2 30m9 = (5m3) 2 (iv) 49y 2 84yz36z 2 Ans Given 49y 2 84yz36z 2

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Divide y, the coefficient of the x term, by 2 to get \frac{y}{2} Then add the square of \frac{y}{2} to both sides of the equation This step makes the left hand side of the equation a perfect square∵ x4 (y z)4 = x22 (y z)22 = (x2) (y z)2 (x2) (y z)2 Using a2 b2 = (ab)(ab)We can factorise x2 (y z)2 further as x2 (y z)2Since x^2y^2=\frac12\left((xy)^2(xy)^2\right) the minimum comes when xy is smallest, that is 1 if xy is odd Thus, the minimum is \frac12\left((xy)^21\right) Since x 2 y 2 = 2 1 ( ( x y ) 2 ( x − y ) 2 ) the minimum comes when ∣ x − y ∣ is smallest, that is 1 if x y is odd

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 · x^2xy y^2 this equation can't be factor because there is no two numbers whose product and sum is oneFactorise the following (i) 4x^2 9y^2 25z^2 12xy 30yz xz (ii) 25x^2 4y^2 9z^2 – xy 12yz – 30xz asked Oct 30, in Algebra by Darshee ( 491k points) algebra · Ex 141, 2 (Method 1) Factorise the following expressions (x) a𝑥^2y bx𝑦^2 cxyza𝑥^2y = a × 𝑥^2 × y = a × 𝑥 × 𝑥 × yb𝑥𝑦^2 = b × 𝑥 × 𝑦^2 = b × 𝑥 × y × yc𝑥𝑦𝑧 = c × 𝑥 × y × zSo, x and y are the common factorsa𝑥^2y b〖𝑥𝑦〗^2 c𝑥𝑦𝑧 = (a × 𝑥 × 𝑥 × y) (b × 𝑥 × y × y) (c × 𝑥 × y

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0118 · Explanation Making m = x −y n = y −z p = x −z we have m2 n2 p2 = 2(x2 y2 z2 − x ⋅ y − x ⋅ z −y ⋅ z) then x2 y2 z2 −x ⋅ y − x ⋅ z − y ⋅ z = 1 2((x − y)2 (y − z)2 (x −z)2)Get your answers by asking now Ask Question 100 Join Yahoo Answers and get 100 points today Join · Read as factorize x y whole squared 2(xy) Yahoo Answers is shutting down on May 4th, 21 (Eastern Time) and beginning April th, 21 (Eastern Time) the Yahoo Answers website will be in readonly mode

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